In Challenge .asm file is Given, We can Understand Given code and make Python Script for That, Although file contains [pdp11](https://en.wikipedia.org/wiki/PDP-11_architecture) Assembly .

```
.MCALL .TTYOUT,.EXIT
START:
mov #MSG r1
mov #0d r2
mov #32d r3
loop:
mov #MSG r1
add r2 r1
movb (r1) r0
.TTYOUT
sub #1d r3
cmp #0 r3
beq DONE
add #33d r2
swab r2
clrb r2
swab r2
br loop
DONE:
.EXIT

MSG:
.ascii "cp33AI9~p78f8h1UcspOtKMQbxSKdq~^0yANxbnN)d}k&6eUNr66UK7Hsk_uFSb5#9b&PjV5_8phe7C#CLc#<QSr0sb6{%NC8G|ra!YJyaG_~RfV3sw_&SW~}((_1>rh0dMzi><i6)wPgxiCzJJVd8CsGkT^p>_KXGxv1cIs1q(QwpnONOU9PtP35JJ5<hlsThB{uCs4knEJxGgzpI&u)1d{4<098KpXrLko{Tn{gY<|EjH_ez{z)j)_3t(|13Y}"
.end START

```

**Python Script**

```
str="cp33AI9~p78f8h1UcspOtKMQbxSKdq~^0yANxbnN)d}k&6eUNr66UK7Hsk_uFSb5#9b&PjV5_8phe7C#CLc#<QSr0sb6{%NC8G|ra!YJyaG_~RfV3sw_&SW~}((_1>rh0dMzi><i6)wPgxiCzJJVd8CsGkT^p>_KXGxv1cIs1q(QwpnONOU9PtP35JJ5<hlsThB{uCs4knEJxGgzpI&u)1d{4<098KpXrLko{Tn{gY<|EjH_ez{z)j)_3t(|13Y}"
i=0
j=32
flag=""
while j>0:
flag+=(str[i%len(str)])
i+=33
j-=1
print(flag)

Just Run It for **flag:cybrics{pdp_gpg_crc_dtd_bkb_php}**

```