Tags: aes crypto 

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## Solution Overview

We analyze the code to realize that __a partial key is given in the ciphertext__ which allows us to use brute force to get the plaintext since key differs by exactly one byte for each round.

__For full implementation and solution see the URL__

Original writeup (https://github.com/pberba/ctf-solutions/tree/master/20181025_bsidesdelhi/crypto-150-pyqueue).