Rating:

# Sign Me Up

```python
from message import *

n, e = 20312493432722984634615913227523125265781662152013094377607630781356105942700273581600613724248110835803158659086732527322062709047441686884292861771528866639670389435647460159612029672461252955594829829663172687201461554413049025271464412190235617740846789840419025423396967519520427432799227162339126087426790939948330768088600429869826069490486741417370162186831426441346576810446894902659826134877586519596679449287778809427232767231366708775004671368581690484301650399106765403344734339945464967775820750215294237822308697430395972800155973323880641007064174229976873404987801414040860359400339131120435868680687, 65537

out = ''
for l in c:
for j in range(32, 127):
if pow(j, e, n) == l:
out += chr(j)
break
print(out)
```

`auctf{D0nT_5igN_r4nd0m_Cr4P_w1tH_y0uR_pr1vAT3_k3y_d00d}`

Original writeup (https://github.com/archercreat/CTF-Writeups/blob/master/auctf/crypto/Sign%20Me%20Up/README.md).