Rating:
# pearl pearl pearl
The challenge is on a service at `95.216.233.106:26551`
connecting to the service shows:
```
$ nc 95.216.233.106 26551
ctf{pearlpearlpearl}
ctf{pearlpearlpearl}
ctf{pearlpearlpearl}
ctf{pearlpearlpearl}
ctf{pearlpearlpearl}
ctf{pearlpearlpearl}
ctf{pearlpearlpearl}
ctf{pearlpearlpearl}
ctf{pearlpearlpearl}
ctf{pearlpearlpearl}
ctf{pearlpearlpearl}
ctf{pearlpearlpearl}
ctf{pearlpearlpearl}
ctf{pearlpearlpearl}
...
```
The flag for this challenge was hidden in the new line characters
I then extracted the new line characters using python and converted the binary characters to the flag
```python
import socket
hostname = '95.216.233.106'
port = 18058
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.connect((hostname, port))
totalData = ''
while True:
data = s.recv(100000)
if len(data) > 0:
totalData += str(data).replace('ctf{pearlpearlpearl}','').replace('pearl','')
else:
break
Binary = ''
count = 0
for char in totalData:
if char == 'r':
Binary += '0'
count += 1
if char == 'n':
Binary += '1'
count += 1
if count == 8:
Binary += ' '
count = 0
flag = Binary.split()
for binary in flag:
print(chr(int(binary,2)), end='')
print()
s.close()
```
**ractf{p34r1_1ns1d3_4_cl4m}**
