Rating:

## Solution Steps
* In the set {0,1,2,...,9}, there are 10 possible values which can be placed in 8 different places, so 10^8 leads to 100,000,000 possible combinations.
* 1st attempt - 1/100,000,000. 2nd attempt - 1/99,999,999. 3rd attempt - 1/99,999,998 = The probability is 0.00000001 or 0.000001%.
* Flag: `jctf{0.00000001}` or `jctf{0.000001%}` or `jctf{1.00000002e-8}` or `jctf{1.00000002x10^-8}` or `jctf{0.0000000100000002}` or `jctf{0.00000100000002%}` or `jctf{.00000001}` or `jctf{.000001%}` or `jctf{.0000000100000002}` or `jctf{.00000100000002%}`

## Knowledge and/or Tools Needed
* [MITRE ATT&CK® Technique T1110.001 - Brute Force: Password Guessing](https://attack.mitre.org/techniques/T1110/001/)
* [NIST 800-30 Guide for Conducting Risk Assessments](https://csrc.nist.gov/publications/detail/sp/800-30/rev-1/final)
* [AAMI TIR57 Principles for Medical Device Security - Risk Management](https://webstore.ansi.org/standards/aami/aamitir572016)
* [Health Insurance Portability and Accountability Act of 1996 - HIPAA](https://www.hhs.gov/hipaa/for-professionals/security/laws-regulations/index.html)

Original writeup (https://github.com/Git-Logan/jerseyctf-challenge-development/tree/main/2023/what-are-the-odds).