The image is a photo of Richard Hamming. The entire image can be interpreted as a 65536-bit Hamming Code in SECDED (extended) mode. To find the error bit, treat the entire image as a 1D array of bits with black pixel = 1 and white pixel = 0 (the inverse will also work). Then, XOR together the **indices** of the 1 pixels, we get 19589, which corresponds to pixel (133, 76).

Hence the flag is `texsaw{one_hundred_and_thirty_three_seventy_six}`

A Python solution script:

```
import numpy as np
from functools import reduce
import operator as op
from PIL import Image

img = Image.open("message.bmp", "r")
width, height = img.size
pixels = list(img.getdata())

def find_faulty_bit(bits):
onelist = [i for i, bit in enumerate(bits) if bit]
faultybit = reduce(op.xor, onelist)
return faultybit

fb = find_faulty_bit(pixels)

print(fb)
print((fb%width, fb//width))
print((bin(fb%width), bin(fb//width)))

```