# XOR

Here's the challenge:

```
fbf9eefce1f2f5eaffc5e3f5efc5efe9fffec5fbc5e9f9e8f3eaeee7
```

Its very basic xor challenge, it must be single byte xor cipher and write a quick bruteforce python2 script

Here's the script:

``` python
cipher = 'fbf9eefce1f2f5eaffc5e3f5efc5efe9fffec5fbc5e9f9e8f3eaeee7'.decode('hex')

for i in range(0x00,0xff):
result = ''
for j in cipher:
result += chr(i^ord(j))
if 'actf{' in result:
print 'flag :', result
```

So flag must be:

```
actf{hope_you_used_a_script}
```

Original writeup (https://github.com/ozancetin/CTF-Writeups/blob/master/2018/angstromCTF2018/XOR/README.md).