Rating:
Ghettohackers: Throwback
------------------------
A .txt file is provided with the following content:
```
Anyo!e!howouldsacrificepo!icyforexecu!!onspeedthink!securityisacomm!ditytop!urintoasy!tem!
```
Given that our brains have been compromised since a long time by playing too many CTFs, we quickly figured out that it was enough to count the number of chars before each `!` to get the index of a single letter of the flag. For instance, `Anyo! = d` because there are 4 chars before the `!` and so we must consider the 4th letter of the English alphabet.
Python one-liner to solve the challenge:
```python
>>> import string
>>> s = 'Anyo!e!howouldsacrificepo!icyforexecu!!onspeedthink!securityisacomm!ditytop!urintoasy!tem!'
>>> ''.join(string.ascii_lowercase[len(c)-1] if c else ' ' for c in s.split('!')).rstrip()
'dark logic'
```
Flag: `dark logic`
