Tags: python
Rating: 2.0
# b01lers
b01lers crypto world, on this write-up i'am using python 2 or 3 for solve this challenge.
## G1
```python
for number in range(1,1000):
if(number % 5 == 2):
if(number % 7 == 6):
if(number % 13 == 9):
print number
number -= 1
```
Flag: **mini{G1_92e9a33c80ca7666c7f4b704}**
## K1
```python
for x in range(1,100000):
for y in range (1,100000):
if ((76*x + 221*y) % 281 == 85):
if ((171*x + 190*y) % 281 == 138):
print str(x) + ',' + str(y)
x -= 1
y -= 1
```
Flag: **mini{K1_cc1c3c9a5695228061017a76}**
## D1
```python
for x in range(1,1000):
if (11**x % 101 == 27):
print(x)
x += 1
```
Flag: **mini{D1_77858210bb3c8f6f90642947}**
## C1
```python
for x in range(1,1000):
if (x**2 % 97 == 88):
print x
```
Flag: **mini{C1_4c88b7b4c11a9ee43f33e130}**
## J1
```python
for x in range(1,1000,1):
for y in range(1,1000,1):
if(x**2 + 22*y**2 == 8383):
print(str(x) + ' , ' + str(y))
```
```
ans 21 , 19
```
Flag: **mini{J1_c9d7861b2635ebb151b71351}**
## G2
```python
print("FIRST STAGE")
xmod5 = []
for x in range(1000000000,10000000000,1):
if (x % 1277 == 616):
xmod5.append(x)
print("SECOND STAGE")
xmod3911 = []
for y in xmod5:
if (y % 3911 == 1892):
xmod3911.append(y)
print("THIRD STAGE")
xmod6833 = []
for z in xmod3911:
if (z % 6833 == 3267):
xmod6833.append(z)
print("RESULT")
print(xmod6833)
```
ans 6429412122
**output:**
```python
FIRST STAGE
SECOND STAGE
THIRD STAGE
RESULT
[6429412122]
```
Flag: **mini{G2_9aa73c3f86221f07d9b789a9}**
