Yep, the CTF is only 3 days away and there is no CTF description here and the CTF website is not up-to-date at all.

Now the updated site is online

Registration is broken: {"msg":"invalid post param: uid","key":"uid","err":"param"}

Cannot register even through an account at XCTF. Google translates says this at XCTF page:

Participation BCTF 2016
XCTF-Time as XCTF League standings and statistics management platform. Each race game platform independence.
Before the game at 20:00 on the 1st before registration in XCTF-Time and join a team of players can participate in the contest.
Players can view account information entry through this page. Entry information will be released before the game at 23:00 on the 1st in XCTF-Time, please be patient.
No XCTFTIME your entry information.
Please visit http://bctf.cn/ participate in the contest.
If you have questions, please mail or through sub-races IRC contact the administrator.

Could somebody write a write-up for task "Hyper RSA / 500"?

@warchantua there was nothing interesting there, just very tedious and time-consuming calculations. It was a meet-in-the-middle attack. You could recover P1, P2 and Q1, Q2 from the server by sending some E (eg. 3, and 65537) values and getting D1 and D2 values for them (this you could do with https://sourceforge.net/projects/rsaconverter/). And then you had to encrypt the given plaintext single time via RSA for all possible E values (up to 9 digit numbers), and decrypt corresponding ciphertext for all D values (so you again iterate over all possible E values up to 9 digit numbers and calculate D value for it). This way you have a very long (gigabytes long...) list of single RSA encrypted plaintext and single RSA decrypted ciphertext and there should be the same row in both of them. This row gives you E1, and E2 used by the server, which you can then use to decrypt the flag.

Please submit scoreboard to CTFTime, thanks